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2x^2=46x+46
We move all terms to the left:
2x^2-(46x+46)=0
We get rid of parentheses
2x^2-46x-46=0
a = 2; b = -46; c = -46;
Δ = b2-4ac
Δ = -462-4·2·(-46)
Δ = 2484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2484}=\sqrt{36*69}=\sqrt{36}*\sqrt{69}=6\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-6\sqrt{69}}{2*2}=\frac{46-6\sqrt{69}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+6\sqrt{69}}{2*2}=\frac{46+6\sqrt{69}}{4} $
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